Re: Dices probability
Posted: 29 December 2022, 23:09
I agree with OP. The die rolls on this site are not random. Too many low probability events happen (at least in my games).
You have played a total of 127 games on this site. I think you should expand your pool of examples, or at elast give some examples in your games of very rare rolls(such as someone rolling 6 same faces multiple times in a so called random manner).WuhanLabTech wrote: ↑29 December 2022, 23:09 I agree with OP. The die rolls on this site are not random. Too many low probability events happen (at least in my games).
Thanks, I found it funny, too.Ez0ah wrote: ↑26 December 2022, 17:52Yeah, you are speaking about feelings here. You are biaised to see the unlikely successes and forget about the majority of average results.adrianbouvier wrote: ↑26 December 2022, 15:00 I am not speaking about feelings here, i am doing maths.
Also, 20 games is a statistically small sample compared to the thousands of games every day. So you could have had very lucky events in your games and it still wouldn’t prove anything. Accusing players of cheating based on a few random games is just pretty funny.
Romain672 wrote: ↑29 December 2022, 13:56 Probability to get exactly 2 hearts in first roll: 1/6*1/6=1/36
Probability to get exactly 1 heart in first roll: 1/6*5/6+5/6*1/6=10/36
Probability to get exactly 0 heart in first roll: 5/6*5/6=25/36
You can see: 1/36+10/36+25/36 add up to 36/36, so 1.
Then you roll a second time:
If you rolled 2 hearts in first roll, the probability to get 0 more heart in the second roll is 1/1, 100%. So we keep that 1/36
If you rolled 1 heart in first roll, the probability to get 1 more heart in the second roll is 1/6, so 10/36*1/6=10/216
If you rolled 0 heart in first roll, the probability to get 2 more hearts in the second roll is 1/6*1/6, so 1/36. 1/36*25/36=25/1296
Then we add up all three, and get: 36/1296+60/1296+25/1296=121/1296.
Which give 9.34% in your simple situation.
I gave you why you are not the first one to think that probabilities is wrong in my first post, and the probability to get 6 hearts in 3 rolls (I will not detail though, since it's pretty complicated, but you can just apply the same thing that what I did here).