CaptainDex wrote: ↑02 February 2025, 19:43 According to my probability calculation, the chance of getting such a game is ~1:500,000, and in only 11% of these games the player would have a chance of getting 5 of the 8 fours rolled, so the value is far outside the norm at ~1:5,000,000 in around 4,600,000 games on BGA, a true phenomenon.
Add to that the luck of occupying both four fields at the beginning.
Ok let's see that one.
So it was this game: https://boardgamearena.com/gamereview?table=624492989 .
So firstly those 27 8s and 2 5s are probabilities. You got 27% of 8s and 2% of 5.
Here is the real rolls:
2 3 4 5 6 7 8 9 10 11 12
0 2 4 1 8 7 14 5 6 2 2
So here you got 51 rolls, 1 being 5 and 14 being 8.
If you double that which I suppose is what CaptainDex did, you will find more extreme probabilities.
Zero or one 5 is at 1.82%
Forteen or more 8 is at 0.818%
So let's keep that forteen 8s, and let's apply my formula: 1-(1-0.00818)^22, we got 16.5%.
Which mean that if you play 6 games, you should have one game where one number is too much or too few rolled as unlikely as that one.
(Zero 2 in 51 rolls is 23.7%)
To be fair, that ^22 isn't great, but that's a way to be fast in calculation. I suppose I should do ^20 or ^18 instead since it's unlikely to get 2s/3s/11s/12s too few rolled being the weirdest thing. But then that should still be 1/7 game instead of 1/6.