I'm running small tournaments of friends and family, 9 people total, so we're splitting into groups of 3 and playing 3-player games using the Swiss system.
If I choose the "don't try and match to the same opponent" option, and I only do 4 rounds of matches, then technically each player should be able to play every other player exactly one time, effectively creating a 3-player round robin of sorts.
What are the chances of this actually working, though? This is actually a difficult math problem called the "Social Golfer problem" https://en.wikipedia.org/wiki/Social_golfer_problem. It has been solved for up to 10 rounds (with 4 player games), so I would propose we are given an option to choose one of these configurations ahead of time.
Pie in the sky, I'm sure, but come on, we're board gamers here. These are exactly the puzzles we like to figure out.
If I choose the "don't try and match to the same opponent" option, and I only do 4 rounds of matches, then technically each player should be able to play every other player exactly one time, effectively creating a 3-player round robin of sorts.
What are the chances of this actually working, though? This is actually a difficult math problem called the "Social Golfer problem" https://en.wikipedia.org/wiki/Social_golfer_problem. It has been solved for up to 10 rounds (with 4 player games), so I would propose we are given an option to choose one of these configurations ahead of time.
Pie in the sky, I'm sure, but come on, we're board gamers here. These are exactly the puzzles we like to figure out.