I created a Swiss System tournament, with a default of 5 players per match, minimum 3 players per match. There were 81 entrants. I'd have expected each round of the tournament to comprise
either:
14 tables of 5, 2 tables of 4, 1 table of 3 (70 + 8 + 3 = 81),
or
15 tables of 5, 2 tables of 3 (75 + 6 = 81).
But instead, Step 1 of the tournament comprises
8 tables of 5, 8 tables of 4, 3 tables of 3 (40 + 32 + 9 = 81).
I'm not complaining, just curious: what is the formula for deciding how many 5-player tables there will be, in a case like this? Why did the server set only 8 tables with a "full" complement of 5 players, when it could have set 14 or 15 tables of 5?
The tournament URL is:
https://boardgamearena.com/tournament?id=187750