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How is player/turn order determined
Posted: 04 November 2024, 18:16
by NiffTheNerd
How is player/turn order determined? I've played 14 games of Catan so far and from what I remember I've been the last player to place my starting settlements for 12-13 of those games. Sometimes being last is an advantage, but I've found myself getting more frustrated by the position because more often than not by the time it's my turn the places I wanted to place my starting settlements have been taken and I have to come up with another strategy that I like less. It clearly isn't determined randomly, so how is the order determined?
Re: How is player/turn order determined
Posted: 04 November 2024, 18:35
by Jellby
Re: How is player/turn order determined
Posted: 04 November 2024, 18:43
by Romain672
It's really likely you just remember badly, and you are first or second more often.
Let's see: 323 323 33
3 332
43
Uh that was right.
I did 10k simulations, 4 of them were as unlucky or more unlucky than you (sum of starting positions). So it's 0.04% .
Just play more, look like you was just extremely unlucky

Re: How is player/turn order determined
Posted: 04 November 2024, 18:57
by NiffTheNerd
Didn't realize you could go back and look at the game log like that, thank you for sharing that info!
And thanks for reminding me that being unlucky doesn't mean that something isn't random. I'm sorry if it sounded like I was complaining, I was just genuinely curious and I guess some of my frustration seeped in. I assumed it was random, but from my experience it seemed incredibly unlikely (as you pointed out) so I wanted to check if there was some other mechanism at play (like ELO ranking or being a premium player).
Romain672 wrote: ↑04 November 2024, 18:43
It's really likely you just remember badly, and you are first or second more often.
Let's see: 323 323 33
3 332
43
Uh that was right.
I did 10k simulations, 4 of them were as unlucky or more unlucky than you (sum of starting positions). So it's 0.04% .
Just play more, look like you was just extremely unlucky
Haha this response was great!
Thanks y'all for confirming I have bad luck, hopefully I'll get more variety in my placements in the future.

Re: How is player/turn order determined
Posted: 04 November 2024, 19:09
by Mathew5000
Jellby wrote: ↑04 November 2024, 18:35The probability of not being first in any of those games is around 1 in 230.
You mean 1 in 292, right?
(2/3)^14 = 1 / 291.92926
Otherwise Jellby is correct, there's no reason to suspect that the turn order is anything other than random. (Except in the case where the game log at the start says "rematch with same players detected" or words to that effect, and rotates the previous turn order; see
https://boardgamearena.com/bug?id=110152 ).
I am interested in opinions on whether it tends to be advantageous or not to go first in Catan. My impression is that in 4-player games, there's often a disadvantage to having first selection, because there's frequently two or three spots for a first settlement that are almost equally good. In 3-player games there's much less of a disadvantage to going first, because when you place your second settlement with only five other settlements placed on the board, you typically still have lots of good options.
Of course this depends on the exact placement of hexes at the particular table.
Re: How is player/turn order determined
Posted: 04 November 2024, 20:47
by Jellby
Mathew5000 wrote: ↑04 November 2024, 19:09
Jellby wrote: ↑04 November 2024, 18:35The probability of not being first in any of those games is around 1 in 230.
You mean 1 in 292, right?
(2/3)^14 = 1 / 291.92926
No, because there are two 4-player games among those.
(2/3)^12 * (3/4)^2 = 1 / 230.66015625
Re: How is player/turn order determined
Posted: 04 November 2024, 23:04
by Mathew5000
Jellby wrote: ↑04 November 2024, 20:47
Mathew5000 wrote: ↑04 November 2024, 19:09
Jellby wrote: ↑04 November 2024, 18:35The probability of not being first in any of those games is around 1 in 230.
You mean 1 in 292, right?
(2/3)^14 = 1 / 291.92926
No, because there are two 4-player games among those.
(2/3)^12 * (3/4)^2 = 1 / 230.66015625
Oops, I didn't see that. Sorry, you're right.
Re: How is player/turn order determined
Posted: 05 November 2024, 18:34
by TheBestMrDudeMan
Looks like we have a good "old-timey" 'math-off' happening here!

Re: How is player/turn order determined
Posted: 07 November 2024, 02:52
by Pedroxsimoes
The order of play should be done by rolling the dice and the final result by the highest total number of dice.
There are maps that have first-to-play advantages.
The game was fair for everyone.